Question

(dividing polynomials)
simplify and show step by step
(a^3b^2-a^2b+2a)(-ab)-^1

Answer 1

\(\bf a^{-{\color{red} n}} = \cfrac{1}{a^{\color{red} n}}
\\ \quad \\ \quad \\

(a^3b^2-a^2b+2a)(-ab)^{-1}\implies
a^3b^2-a^2b+2a\cdot \cfrac{1}{(-ab)^1}
\\ \quad \\
\cfrac{a^3b^2-a^2b+2a}{(-ab)}\implies \cfrac{\cancel{ a^3b^2 }}{-\cancel{ ab }}-\cfrac{\cancel{ a^2b }}{-\cancel{ ab }}+\cfrac{2\cancel{ a }}{-\cancel{ a }b}\implies ?\)