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Mathematics 8 Online
OpenStudy (anonymous):

One night, the movie theater sold 715 movie tickets. The ticket prices are shown in the table below. In all, $3,786.50 was taken in. How many of each kind of ticket were sold at the movies? Show your work.

OpenStudy (anonymous):

OpenStudy (briana.img):

a + c = 715 ---->(a = 715 - c) 6.50a + 3.50c = 3786.50 now sub 715 - c in for a in the 2nd equation

OpenStudy (briana.img):

a + c = 715 --- adult + child = 715 tickets 6.50a + 3.50c = 3786.50 -- 6.50 adult tickets + 3.50 child tickets = 3786.50 a + c = 715 --> a = 715 - c now we sub 6.50a + 3.50c = 3786.50 6.50(715 - c) + 3.50c = 3786.50 --- distribute through the parenthesis 4647.50 - 6.50c + 3.50c = 3786.50 -- subtract 4647.50 -6.50c + 3.50c = 3786.50 - 4647.50 -- combine like terms -3c = - 861 c = 287 a + c = 715 a + 287 = 715 a = 715 - 287 a = 428 check.. 6.50(428) + 3.50(287) = 3786.50 2782 + 1004.50 = 3786.50 3786.50 = 3786.50 (correct) adult tickets (a) = 428 child ticlets (c) = 287

OpenStudy (anonymous):

wow thanks that helped so much!! I understand now

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