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\[111=100\times (1.0153)^x\] solve for \(x\) do you know how to do that?
just asking...
Would it be 6.87?
hold on let me check
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yes it is
okay
now what do i do
that is all oh i see you have to answer the question it says round, so round to seven years
7 years after 2000 is evidently 2007
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Makes sense, thank you!
yw
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