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Geometry 16 Online
OpenStudy (anonymous):

Calculate the total area of the triangular prism https://media.glynlyon.com/g_geo_2013/8/groupi68.gif

OpenStudy (anonymous):

Any idea?

OpenStudy (anonymous):

i know that total area is the lateral area + combined area of the two bases. i just don't know which numbers to plug in or determine

OpenStudy (anonymous):

|dw:1405733030131:dw|

OpenStudy (anonymous):

2

OpenStudy (anonymous):

so, total area of this part is \(2*(\dfrac{1}{2}*4*6)=24\) right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

you still have lot of things to do, not done yet. I guide you step by step. Let say it is part 1, you have area1 =24, let it there. Now, by pythagorean, what is the hypotenuse of the triangle? |dw:1405733332645:dw|

OpenStudy (anonymous):

52

OpenStudy (anonymous):

no wait

OpenStudy (anonymous):

2 sqrt 13 right?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

rewatch

OpenStudy (anonymous):

|dw:1405733632156:dw|

OpenStudy (anonymous):

you have only 1, it is in the front, right?

OpenStudy (anonymous):

yeah sorry i was thinking the one in the back too but they don't have the same measurements

OpenStudy (anonymous):

ok, let say it is part 2, and the area 2 = ?? (rectangle with the width =\(2\sqrt{13}\) and the length =8 )

OpenStudy (anonymous):

\[16\sqrt{13}\]

OpenStudy (anonymous):

good, so far we have area1 and area2, right? Now, area 3, let see !! how about area of this??|dw:1405733993657:dw|

OpenStudy (anonymous):

32

OpenStudy (anonymous):

good job, how about area 4 which is |dw:1405734142895:dw|

OpenStudy (anonymous):

48

OpenStudy (anonymous):

hihihi, Now, just add them all, you have the answer, right?

OpenStudy (anonymous):

|dw:1405734227576:dw| got it?

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