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solve the system using substation. Enter answer in ordered pair form (a,b) a+b=4 2a+3b=11
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First isolate b in a+b=4 to get... a+b=4 a+b-a=4-a b = 4-a
Then plug this into 2a+3b=11 to get 2a+3b=11 2a+3(4-a)=11 ... replace b with 4-a ------------------------------------------------------- solve for 'a' in the equation 2a+3(4-a)=11 gives you a = ???
what do you get when you distribute 3(4-a)
12-3
12-3a actually
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2a+3(4-a)=11 2a+12-3a=11 -a+12 = 11 a = ???
id subtract12 from 11 correct?
correct
minus 12 on both sides so you get an equation that looks like -a = -1
-a = 11 - 12 -a = -1 a = 1
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Once you know a = 1, use it to find that b = 4-a b = 4-1 b = 3
oh okay o get it.
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