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OpenStudy (anonymous):
Log2x - log(1-x)=-2
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OpenStudy (aum):
log(A) - log(B) = log(A/B) Use the above identity to simplify the left hand side first. What do you get?
OpenStudy (anonymous):
X
OpenStudy (anonymous):
log(2x/1-x)= -2
OpenStudy (aum):
Yes, log(2x/1-x)= -2 which implies 2x/(1-x) = 10^-2 = 1/100 solve for x.
OpenStudy (anonymous):
Is it -1
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