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If the perimeter of the triangle below is 41, find the value of x. A. 3 B. 17 C. 9 D. 15
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well so 6x - 3 + 5x + 2 + 3x = 14x - 1 = 41
can u solve for x then?
Now, how would I do that?
well you can add 1 to both sides : 14x -1 + 1= 41 + 1 --> 14x = 42 and now divide both sides by 14 and simply write : x = 3
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Ah, I see. I'll try that on a similar problem. Thanks!
you're welcome ;)
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