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Mathematics 6 Online
OpenStudy (kohai):

Solve for x and determine if the solution is extraneous or not

OpenStudy (kohai):

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OpenStudy (kohai):

@iPwnBunnies

OpenStudy (abmon98):

(3/x-3)-x/x-3=-3/2 3-x/x-3=-3/2 -x+3/x-3=-3/2 2(-x+3)=-3(x-3) -2x+6=-3x+9 -x=-3 x=3

OpenStudy (kohai):

And so the solution would be extraneous?

OpenStudy (abmon98):

i don't know whats extraneous or non extraneous

OpenStudy (kohai):

Extraneous is when you plug it into the equation and the solution isn't equal to each other. Most of the time you solve for x and you plug it back in and the solution is equal but if it's non extraneous then they are unequal

OpenStudy (abmon98):

(3/3-3)=3/3-3-3/2 0=-3/2 they are unequal then its non extraneous

OpenStudy (kohai):

Thanks

OpenStudy (abmon98):

your most welcome :D

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