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Physics 18 Online
OpenStudy (anonymous):

A particle has an acceleration of +6.24 m/s2 for 0.300 s. At the end of this time the particle's velocity is +7.81 m/s. What was the particle's initial velocity?

OpenStudy (abhisar):

v=7.81 a=6.24 t=0.3 u=? use v=u+at and find u

OpenStudy (anonymous):

u=5.9

OpenStudy (abhisar):

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