Please help me "Solve square root of the quantity x minus three equals square root of two minus square root of x for x" A:25/8 B:no solution C:-25/8 D:1/8
\(\normalsize\color{blue}{ \sqrt{x-3}= \sqrt{2} - \sqrt{x} }\) like this ?
Yes
\(\normalsize\color{blue}{ \sqrt{x-3}= \sqrt{2} - \sqrt{x} }\) square both sides, and you get \(\normalsize\color{blue}{ x-3= 2 - \sqrt{2x} +x }\) \(\normalsize\color{blue}{ x-3\color{red}{ -2-x }= 2 - \sqrt{2x} +x \color{red}{ -2-x } }\) \(\normalsize\color{blue}{ -5= - \sqrt{2x} }\) \(\normalsize\color{blue}{ 25= 2x }\)
\(\normalsize\color{blue}{ x=? }\)
The equation was suppose to solve for x, no x value was given.
does that mean the answer is B, no solution?
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