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Calculus1
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how do i simplify 3 cos^2 x + 3 cos^2 x tan^2 x
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\[\tan^2x=\frac{\sin^2x}{\cos^2x}\] so \[\cos^2x\tan^2x=\sin^2x\] \[3\cos^2x+3\sin^2x=3\left(\cos^2x+\sin^2x\right)=\cdots\]
and remember \[\cos^{2}x + \sin^{2}x = 1\] :)
thanks guys!
yw
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