Question

Identify the factors of x^2 - 8x - 20.

(x + 4)(x - 5)

(x + 5)(x - 4)

(x - 10)(x + 2)

(x - 2)(x + 10)

Answer 1

Factor the following:
x^2-8 x-20
Factor x^2-8 x-20 by finding two numbers whose product is -20 and whose sum is -8.
The factors of -20 that sum to -8 are 2 and -10. So, x^2-8 x-20 = (x+2) (x-10):
so the answer is
| (x+2) (x-10)

Answer 2

this is the middle term break method
x^2+2x -10x -20 =0
x(x+2) -10(x+2)=0
(x-10)(x+2) is the correct answer

Answer 3

Thank you!

Answer 4

most welcome my dear