Question

The height of a cylinder with a fixed radius of 10 cm is increasing at the rate of 0.5 cm/min. Find the rate of change of the volume of the cylinder (with respect to time) when the height is 30cm.

Answer 1

this link would help u buddy https://www.jackmathsolutions.com/images/CHAPTER_8.pdf

Answer 2

Do you know the formula for volume of cylinder?

Answer 3

\[\LARGE V= \pi r^2 H\]
Differentiate wrt to time
\[\LARGE \frac{dV}{dt} = \pi r^2 \times \frac{dh}{dt}\]
Note that r is given constant here.
Use the info from your question that:
r=10
dr/dt= 0.5
h=30
Substitute everything and solve for LHS.

Answer 4

Thanks, I already got, actually finding that link on my own @gowtham89 lol