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Integration.
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expand (x-1)^2 and separate out the numerator
(x-1)^3
then each term will be of the form x^n
x^3 - 3x^2 + 3x - 1
yes, divide each term by x^2
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x-3+3/x -1/x^2
then integrate this.. am i right? yes
yep, now integrate each term
so what did u get ?
x-3 + 3 ln x - 1/x +c
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integral of x is x^2/2
integral of -3 is -3x
ah yes. so its x-3x + 3 lnx - 1/x +c
integral of x is x^2/2
integral -1/x^2 is just +1/x
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ah yes yes stupid mistake.. x^2 /2 - 3x + 3 lnx + 1/x +c
now correct :D \(\huge \checkmark \)
Thank you so much
welcome ^_^
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