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Mathematics 7 Online
OpenStudy (anonymous):

Integration.

hartnn (hartnn):

expand (x-1)^2 and separate out the numerator

hartnn (hartnn):

(x-1)^3

hartnn (hartnn):

then each term will be of the form x^n

OpenStudy (anonymous):

x^3 - 3x^2 + 3x - 1

hartnn (hartnn):

yes, divide each term by x^2

OpenStudy (anonymous):

x-3+3/x -1/x^2

OpenStudy (anonymous):

then integrate this.. am i right? yes

hartnn (hartnn):

yep, now integrate each term

hartnn (hartnn):

so what did u get ?

OpenStudy (anonymous):

x-3 + 3 ln x - 1/x +c

hartnn (hartnn):

integral of x is x^2/2

hartnn (hartnn):

integral of -3 is -3x

OpenStudy (anonymous):

ah yes. so its x-3x + 3 lnx - 1/x +c

hartnn (hartnn):

integral of x is x^2/2

hartnn (hartnn):

integral -1/x^2 is just +1/x

OpenStudy (anonymous):

ah yes yes stupid mistake.. x^2 /2 - 3x + 3 lnx + 1/x +c

hartnn (hartnn):

now correct :D \(\huge \checkmark \)

OpenStudy (anonymous):

Thank you so much

hartnn (hartnn):

welcome ^_^

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