Question

Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five.

38 and 40
40 and 42
42 and 44

Answer 1

let that numbers are x and (x+2) respectively.
so,
1/2 (x+2) - 2/5 (x) = 5
multiply 10 on both sides, get
10 * 1/2 (x+2) - 10 * 2/5 (x) = 10 * 5
5(x+2) - 4x = 50
5x + 10 - 4x = 50
x + 10 = 50
x = 50 -10
x = 40
and
the 2nd number = x+2 = 40 + 2 = 42
they are 40 and 42

Answer 2

thank you