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y=x^2-x-23
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y = x^2-x-23 find the vertex The vertex is a point in the form (x,y). We first find x. x = -b/2a x = -(-1)/2(1) x = 1/2
To find y, replace every x in the given function with 1/2 and do the math. y = (1/2)^2-(1/2)- 23 y = 1 - 1/2 - 23 y = -45/2 The vertex is (1/2, -45/2).
is vertex what the question is? or is it the roots?
y=x^2-x-23 Solving the equation for x we get x=(5.32 & -4.32). The mid point is 5.43-4.32=1/2=.5 y=.5^2-.5-23
y=.25-.5-23 y=.25-23.5 y=-23.25 The VERTEX(.5,-23.25)
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