Question

Help me???
Given f (x) = 3x^3 - 4x^2 + x-1 what is f(2)
Factor 36n^2 - 81
Simplify : mm(m^5)^0 m^-3 divided by m^6(y^3)^-3
solve : y^2 = 18

Answer 1

f(2) is simply a case of substituting x = 2 into the equation and evaluating.

36n^2 - 81

this is the difference of 2 squares

36n^2 = (6n)^2 81 = (9)^2


hope it helps

Answer 2

for my first question my answer was 3, am I right?

Answer 3

I don't think so

\[3 \times2^3 - 4 \times 2^2 + 2 - 1\]