Question

What are the end behaviors of f(x) = -2(x - 2)5?

A. Both ends go down.
B. The left end goes up; the right end goes down.
C. The left end goes down; the right end goes up.
D. Both ends go up.

Answer 1

when x → ∞, then `-2(x-2)` is a negative number, and will still remain negative when raised to the fifth power.
when x → -∞, then `-2(x-2)` is a positive number (product of 2 negatives=positive), and raised to the fifth power is positive.

THUS
when x → ∞, f(x) → -∞
when x → -∞, f(x) → ∞

makes sense ?