Question

Help me solve this inequality please. X^2 >-16

Answer 1

The opposite of the square root, so you take the square root of both sides
\(\sqrt{x^2}>\sqrt{-16}\), you can't take a square root of a negative number without it being imaginary.

Answer 2

x^2 is ALWAYS positive.

Therefore it will be ALWAYS greater than a negative number.

So x is ANY real number.