Question

Can somebody please explain in detail why the roots to x2 (x-squared)+9=0 are 3i and -3i?

Answer 1

sure

Answer 2

\[x^2+9=0\\
x^2=-9\\
x=\pm\sqrt{-9}\\
x=\pm\sqrt{9(-1)}\\
x=\pm\sqrt{9}\sqrt{-1}\\
x=\pm3i\]

Answer 3

Thank you! That helps a lot.

Answer 4

yw