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OpenStudy (anonymous):
x^2+square root 19x + 15 over 4=0 completing the square
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OpenStudy (tkhunny):
\(x^{2} + \sqrt{19}x + 15/4 = 0\) \(x^{2} + \sqrt{19}x\;+\;?? = -15/4\;+\;??\) What's stopping you from finding half of \(\sqrt{19}\) and then squaring it? It is the same as any other number in that position.
OpenStudy (anonymous):
what is half of \(\sqrt{19}\) ?
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