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Mathematics 11 Online
OpenStudy (anonymous):

HELP PLEASE! PICTURE ATTACHED!

OpenStudy (anonymous):

OpenStudy (driftracer305):

i would say 8 secs..... because it took it 4 seconds to climb at it's max height... now also 4 sec to reach the ground.......

OpenStudy (driftracer305):

or no wait........ can be 6 secs becausw it says how long will it be in air?

OpenStudy (driftracer305):

any guesses @cheyennestaggs ??

OpenStudy (anonymous):

Not at all .. lol I dont get this

OpenStudy (driftracer305):

yes.... m just confused between 6 and 8......

OpenStudy (driftracer305):

@doulikepiecauseidont ...... do u knw this?

OpenStudy (anonymous):

I would think it's 10 seconds, becuase it took 5 secs to reach the peak of 259 (at t=4 it's a little under 240 so we know it's not the max) and if it follows the normal graph of falling objects in most practice problems it makes a a parabola

OpenStudy (anonymous):

The vertex is the point of symmetry, and that's where it looks the same at both sides

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

What was the answer if you know

OpenStudy (anonymous):

I was not 100%

OpenStudy (anonymous):

I won't know until the end if it was wrong or right lol

OpenStudy (anonymous):

Wait

OpenStudy (anonymous):

Can you go back to your question?

OpenStudy (anonymous):

It is actually 8 seconds

OpenStudy (driftracer305):

lol @doulikepiecauseidont ....... same thoughts i had.... but m 100% sure @cheyennestaggs that it is either 6 or 8 secs

OpenStudy (anonymous):

lol yes thank you. What changed your mind @doulikepiecauseidont and also thak you @driftracer305

OpenStudy (driftracer305):

@cheyennestaggs ?? so wat was the answer thou??

OpenStudy (anonymous):

She doesn't know until she's done, and I was just looking at the graph wrong @cheyennestaggs

OpenStudy (driftracer305):

ohhh ok.... all kool.......... just curious u knw.....

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