The area of the base of Cylinder A is 4 times the area of the base of Cylinder B. What is the radius of Cylinder A (rA) in terms of the radius of Cylinder B (rB)?

a) rA=rB (I know it's not that one)
b) rA=4*rB
c) rA=2*rB
d) rA=rB/4
e) rA=rB/2

Thank you!!!

Question

The area of the base of Cylinder A is 4 times the area of the base of Cylinder B. What is the radius of Cylinder A (rA) in terms of the radius of Cylinder B (rB)?

a) rA=rB (I know it's not that one)
b) rA=4*rB
c) rA=2*rB
d) rA=rB/4
e) rA=rB/2

Thank you!!!

bradely · Answer

πrA^2 = 4πrB^2
 rA^2 = 4rB^2 
Square root on both sides
 rA=2rB 
Option C is correct 
Source:www.mathskey.com

anonymous · Answer

Oh wow, now it makes sense!!! Thank you very much for your help!