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terenzreignz (terenzreignz):
dito.
terenzreignz (terenzreignz):
@swanity punta ka dito haha
terenzreignz (terenzreignz):
dito mo ilagay tanong mo
OpenStudy (anonymous):
2+10+50+250+1250+6250+31250
terenzreignz (terenzreignz):
Okay... ito formula ng sum... idederive ko pa ba para sayo? :D
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terenzreignz (terenzreignz):
Teka...
OpenStudy (anonymous):
bket?
terenzreignz (terenzreignz):
\[\Large S_n = \frac{a(1-r^n)}{1-r}\]
yan pala
terenzreignz (terenzreignz):
Dito, a yung pinakaunang term.
r yung common ratio.
OpenStudy (anonymous):
edi ano yan
A7=7(1-5 tas 7 ung nasa taas nyan)
1-5 ganan lng ba?
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terenzreignz (terenzreignz):
Ano? haha di ko gets ginawa mo :>
OpenStudy (anonymous):
ano sagot nlng dyan
terenzreignz (terenzreignz):
Kailangan mo lang naman malaman kung ano ang a at r eh...
Ano yung a?
(pinakaunang term)
OpenStudy (anonymous):
7 ung a kc 7 ung binigay ko sau
terenzreignz (terenzreignz):
Hinde... a yung pinakaunang term :P
2+10+50+250+1250+6250+31250
Ano ba yung pinakaunang addend dito?
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OpenStudy (anonymous):
2
OpenStudy (anonymous):
a ung 2
terenzreignz (terenzreignz):
a = 2.
Yes.
O, ano yung common ratio r?
OpenStudy (anonymous):
5
terenzreignz (terenzreignz):
Okay. r = 5.
Ngayon, n ay kung ilan lahat ng addends.
YUN ang 7.
haha
\[\Large S_7 = \frac{2(1-5^7)}{1-5}\]
O, kaya mo na yan :D
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OpenStudy (anonymous):
oo nman alam ko na nga sagot ehh
terenzreignz (terenzreignz):
Yun naman pala eh.
Ok na? ^^
OpenStudy (anonymous):
39062 ung sagot
OpenStudy (anonymous):
tama ba?
terenzreignz (terenzreignz):
Oo.. pero syempre, mas madali kung i-google mo na lang yung
2+10+50+250+1250+6250+31250
XD
korni naman ng tanong na ito... kailangan yung mas maraming addends, tipong 200
para di pwede igoogle XD
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OpenStudy (anonymous):
thankz sa susunod nlng ulet pag hindi ko alam
terenzreignz (terenzreignz):
sana naman wala nang susunod...
dapat alam mo na lahat XD