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Algebra 18 Online
OpenStudy (anonymous):

8

terenzreignz (terenzreignz):

dito.

terenzreignz (terenzreignz):

@swanity punta ka dito haha

terenzreignz (terenzreignz):

dito mo ilagay tanong mo

OpenStudy (anonymous):

2+10+50+250+1250+6250+31250

terenzreignz (terenzreignz):

Okay... ito formula ng sum... idederive ko pa ba para sayo? :D

terenzreignz (terenzreignz):

Teka...

OpenStudy (anonymous):

bket?

terenzreignz (terenzreignz):

\[\Large S_n = \frac{a(1-r^n)}{1-r}\] yan pala

terenzreignz (terenzreignz):

Dito, a yung pinakaunang term. r yung common ratio.

OpenStudy (anonymous):

edi ano yan A7=7(1-5 tas 7 ung nasa taas nyan) 1-5 ganan lng ba?

terenzreignz (terenzreignz):

Ano? haha di ko gets ginawa mo :>

OpenStudy (anonymous):

ano sagot nlng dyan

terenzreignz (terenzreignz):

Kailangan mo lang naman malaman kung ano ang a at r eh... Ano yung a? (pinakaunang term)

OpenStudy (anonymous):

7 ung a kc 7 ung binigay ko sau

terenzreignz (terenzreignz):

Hinde... a yung pinakaunang term :P 2+10+50+250+1250+6250+31250 Ano ba yung pinakaunang addend dito?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

a ung 2

terenzreignz (terenzreignz):

a = 2. Yes. O, ano yung common ratio r?

OpenStudy (anonymous):

5

terenzreignz (terenzreignz):

Okay. r = 5. Ngayon, n ay kung ilan lahat ng addends. YUN ang 7. haha \[\Large S_7 = \frac{2(1-5^7)}{1-5}\] O, kaya mo na yan :D

OpenStudy (anonymous):

oo nman alam ko na nga sagot ehh

terenzreignz (terenzreignz):

Yun naman pala eh. Ok na? ^^

OpenStudy (anonymous):

39062 ung sagot

OpenStudy (anonymous):

tama ba?

terenzreignz (terenzreignz):

Oo.. pero syempre, mas madali kung i-google mo na lang yung 2+10+50+250+1250+6250+31250 XD korni naman ng tanong na ito... kailangan yung mas maraming addends, tipong 200 para di pwede igoogle XD

OpenStudy (anonymous):

thankz sa susunod nlng ulet pag hindi ko alam

terenzreignz (terenzreignz):

sana naman wala nang susunod... dapat alam mo na lahat XD

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