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Algebra
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Find the third iterate, x3, of the function f(x) = 3x + 5 for an initial value of x0 = 1
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Iteration is a process by which the output of one step becomes the input for the next one...so that for f(x) = 2x-5 and x(0) = 3 f(x0) = f(3) = 2(3) - 5 = 1 f(x1) = f(1) = -3 f(x2) = f(-3) = -11 f(x3) = f(-11) = -27
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