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Pleae help me simplify this algebraic fraction (not showing up right equation in box below)
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\[\frac{b^2-3b-10}{ (b-2)^2 }*\frac{ b-2 }{ b-5}\] is the algebraic fraction
Do they tell you what b is or do we have to find it?
I dont have to solve only simplify
first factor the trinomial b^2 - 3b - 10 can you do that?
you need to numbers whose product is -10 and whose sum = -3 and they will be of the form (x + a)(x - b)
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(b+2)(b-5)
right now you can simplify
Thanks
not that (b-5) and (b-2) are common factors in top and bottom of the fractions
Yep I canceled out and got \[\frac{ b+2 }{ b-2 }\]
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