optimization I'm almost done just need a little help.

A gardener wishes to enclose a rectanglar area with 300 feet of fencng and fencing down the middle to divide it into 2 equal subareas. What is the largest area that may be enclosed.

I did 2l +2w = 300 l=150-w
l= -b/2a =150/(2*-1) =75

The final answer is 50 * 75 = 3750

Question

optimization I'm almost done just need a little help. 

A gardener wishes to enclose a rectanglar area with 300 feet of fencng and fencing down the middle to divide it into 2 equal subareas. What is the largest area that may be enclosed.

I did 2l +2w = 300 l=150-w 
l= -b/2a     =150/(2*-1) =75

The final answer is 50 * 75 = 3750

thomas5267 · Answer

Could you please define your variables?  What is l, w, b and a?

anonymous · Answer

l= length W= width   the formula for length is -b/2a b is 150 a is -1

thomas5267 · Answer

You have three fences going from up to down.

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