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how do i factor 6y^2-4y-10 ?
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You could use the quadratic formula
or do the snowflake method(also know as diamond)
\[x=\frac{ -b \pm \sqrt{b^{2}-4ac} }{ 2a }\] \[ax2^{2} + bx + c = 0\]
What're your options as far as answers go?
@alg2help the answer is 2(y+1)(3y-5)
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You're correct!!!
alg do you know the snowflake method?
I can't say I do, no! Sorry!
would you like to learn it?
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