Help for medal? Select the equation of the line that passes through the point (3, -1) and is parallel to the line on the graph.
y = -1 y = 3 y = x -1 y = 3x - 1
@aum Help?
How is the link you posted connected to this problem?
I'm not sure it was just with the question.
(3, -1) has a y value of -1. y = -1 is a horizontal line parallel to the x-axis. ANY point that has a y-value of -1 will be on this line. Therefore, (3,-1) will be on this line. Try out other choices to see if there are any other lines that has (3,-1). Put x = 3 and y = -1 in each equation to see if it is valid.
Would it be D?
y = 3x - 1 put x = 3 and y = -1 -1 = 3(3) - 1 LHS is -1 and RHS is 8. So the equation is not satisfied. So D is false.
Is it B?
No. (3,-1) has a y value of -1. In B, y = 3. It does not have a y-value of -1.
I don't see how it could be C then
Join our real-time social learning platform and learn together with your friends!