Question

please solve? I give medals.
4b/9 - b/5=11, solve for b.
a.40
b.45
c.50
d.55

Answer 1

I'll get you started


\[\Large \frac{4b}{9} - \frac{b}{5} = 11\]

\[\Large \frac{5*4b}{5*9} - \frac{9*b}{9*5} = 11\]

\[\Large \frac{20b}{45} - \frac{9b}{45} = 11\]

\[\Large \frac{20b-9b}{45} = 11\]

\[\Large \frac{11b}{45} = 11\]


and I'll let you finish up

Answer 2

its 45, i used my fancy calculator :P

Answer 3

very good, here's how you do it without a calculator

\[\Large \frac{4b}{9} - \frac{b}{5} = 11\]

\[\Large \frac{5*4b}{5*9} - \frac{9*b}{9*5} = 11\]

\[\Large \frac{20b}{45} - \frac{9b}{45} = 11\]

\[\Large \frac{20b-9b}{45} = 11\]

\[\Large \frac{11b}{45} = 11\]

\[\Large 11b = 11*45\]

\[\Large b = \frac{11*45}{11}\]

\[\Large b = \frac{\cancel{11}*45}{\cancel{11}}\]

\[\Large b = 45\]