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What are the solutions of 2x2 + 8x = -26?
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-2 ± 3i -2 ± i 2 ± 6i -3 ± 2i
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2(x^2 + 4x) = -26 x^2 + 4x = -13
Now we use (b/2)^2 which is 4 and add that to both sides: x^2 + 4x + 4 = -9 This is (x+2)^2 = -9 rad both sides x+2 = rad(-9) x + 2 = i * rad(9) x + 2 = +-3i x = -2 +- 3i
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