Solve 3x^2 = -30x + 24. A) quantity of negative 10 plus or minus square root of 33 all over 2 B) negative 5 plus or minus 2 square root of 33 C) negative 10 plus or minus square root of 33 D) negative 5 plus or minus square root of 33
You solve this by moving -3x^2 from both sides so you get an equation that looks like this \[0=-3x^2 -30x+24\] And then you use the quadratic formula to get the answer. Do you know the quadratic formula?
yess
So what answers do you get when you use quadratic formula?
\[30\sqrt{612} \div -6\]
i dont think its right
You have the 30 and -6 part right, but the square root of 612, I don't think is correct. When you apply the quadratic formula the inside of the square root should look like this \[\sqrt{-30^2-4(-3)(24)}\] When you calculate this through, you should get \[\sqrt{1188}\]
Oh yeah one more thing I didn't catch, it should be 30 (plus or minus) square root, not 30 times squareroot.
So it should look like this \[(30(+ or -)\sqrt{1188})/-6\]
\[5\pm2\sqrt{33}\]
The correct answer is \[-5\pm \sqrt{33}\] So to me that sounds like D, but I can't look at what the answers look like, but yeah that's it.
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