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In which function is x = 2 mapped to 32? g(x) =4(x+3)^2-68 h(x)=3x j(x)=2x-62
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just substitute x = 2 into each equation. then the answer is the one that has a function value of 32. so g(2) = 4(2 + 3)^2 - 68 h(x) = 3 * 2 j(x) = 2*2 - 62
which one is it?
well just calculate them out... it should be obvious which is isn't
the third one right?
so 2 times 2 - 62 = 32...?
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or... 4 - 62 = 32....
ill do the next one just what is this one
idk how to solve the fisrt equation
well use pedmas.... brackets 2 + 3 then square that number then multiply it by 4... then subtract 68
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