Question

Find the equation of the quadratic function with zeros 10 and 12 and a vertex at (11, -2).

Answer 1

so is going UP, so is a positive "a" or leading term component

and is opening over the x-axis, or is vertical, meaning the "y" is the squared term so \(\bf y={\color{blue}{ a}}(x-{\color{brown}{ h}})^2+{\color{brown}{ k}} \)