Question

jesus someone please help

















Create a quadratic function, f(x), in vertex form. The a should be between 4 and –4, the h will be your birth month, and the k will be your birth day. Write your equation below.

y = a(x-h)² + k a= 4 -(-4)
h=8 k=16
y=4(x-8)²+16

Using complete sentences, explain how to convert your birthday function into standard form.

8/16/99

Answer 1

This question makes no sense at all (no offense)

Answer 2

but I'm guessing all you do is plug in your birthday into y = a(x-h)² + k and that's all they want? Not sure

Answer 3

i know it doesnt make sense >.<

Answer 4

I'd just skip that problem and move onto other hw problems. Idk what else to say

Answer 5

ok what values of a, h, k are you using?

Answer 6

8 16 and 99 im assuming

Answer 7

oh wait, it says "a" has to be between -4 and 4

Answer 8

so pick another "a" value

Answer 9

4?

Answer 10

that works

Answer 11

a = 4
h = 16
k = 99

so...

\[\Large y = a(x-h)^2 + k\]

\[\Large y = 4(x-16)^2 + 99\]

Answer 12

which takes care of part a)

Answer 13

Then we convert to standard form (to answer part b)


\[\Large y = 4(x-16)^2 + 99\]

\[\Large y = 4(x-16)(x-16) + 99\]

\[\Large y = 4(x^2-32x+256) + 99\]

\[\Large y = 4x^2-128x+1024 + 99\]

\[\Large y = 4x^2-128x+1123\]

Answer 14

oh my gosh thank you so much for your help

Answer 15

np

Answer 16

1. a = 4
h = 16
k = 99

y=a(x-h)^2+k
y=4(x-16)^2+99


2. y=4(x-16)^2+99
y=4(x-16)(x-16)+99
y=4

Answer 17

1. a = 4 h = 16 k = 99
y=a(x-h)^2+k
y=4(x-16)^2+99

2. y=4(x-16)^2+99
y=4(x-16)(x-16)+99
y=4(x^2 – 32x+ 256)+99
y=4(x^2-