Question

@SolomonZelman

Answer 1

please help solomon

Answer 2

can you solve the initial system on number 5 ?

Answer 3

dont really know how

Answer 4

\(\normalsize\color{blue}{ 6x+2y=-6 }\)
\(\normalsize\color{blue}{ 3x-4y=-18 }\)
divide the first equation by `-2` and re-write the system. Then add the equations.
\(\normalsize\color{blue}{ -3x-y=3 }\)
\(\normalsize\color{blue}{ ~^{+} }\) \(\normalsize\color{blue}{ 3x-4y=-18 }\)
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\(\normalsize\color{blue}{ -5y=-15 }\)

\(\normalsize\color{blue}{ y=3 }\)

\(\normalsize\color{blue}{ 6x+2(3)=-6 }\)
\(\normalsize\color{blue}{ 3x-4(3)=-18 }\)

\(\normalsize\color{blue}{ 6x+6=-6 }\)
\(\normalsize\color{blue}{ 3x-12=-18 }\)

\(\normalsize\color{blue}{ 6x=-12 }\)
\(\normalsize\color{blue}{ 3x=6 }\)

\(\normalsize\color{blue}{ x=-2 }\)
\(\normalsize\color{blue}{ x=-2 }\)

\(\normalsize\color{blue}{ (-2,3) }\)

Answer 5

this is the solution to the initial system.

Answer 6

but theres no answer like that @SolomonZelman

Answer 7

this is no the answer, it is the solution to your first system.