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OpenStudy (anonymous):
Write the Expression as a sum and/or difference of logarithms. Express powers as factors. ln[(x^2-x-2)/(x+4)]^(1/3) x>2
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OpenStudy (gorv):
ln[(x^2-x-2)/(x+4)]^(1/3) =(1/3)*[ln(x^2-x-2)-ln(x+4)]
OpenStudy (gorv):
log(a/b)=log a - log b
OpenStudy (anonymous):
Must it be simplified further or is that the final form?
OpenStudy (gorv):
final form it is
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