Question

Write the Expression as a sum and/or difference of logarithms. Express powers as factors.
ln[(x^2-x-2)/(x+4)]^(1/3) x>2

Answer 1

ln[(x^2-x-2)/(x+4)]^(1/3) =(1/3)*[ln(x^2-x-2)-ln(x+4)]

Answer 2

log(a/b)=log a - log b

Answer 3

Must it be simplified further or is that the final form?

Answer 4

final form it is