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In a race, A beats B by 15 metres and C by 29 metres. When B and C run over the course together, B wins by 15 metres. The length of the course is ____
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srry 215 200 171
200 185 171
|dw:1406173894619:dw|
Let the length of the course be x metres. When B runs x metres be gains 15 metres on C. Therefore B gains 1 metre for each x/15 metres that B runs. When B has run x - 15 metres he is 14 metres ahead of C. Therefore we can write: \[\frac{x-15}{\frac{x}{15}}=14\ .......(1)\] Solving equation (1) gives x = 225 metres.
Therefore B gains 1 metre over C for each x/15 metres that B runs.*
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great!:-)
You're welcome :)
confusing slightly
k got it!
Good on you!
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