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verify the identity: cot x/1+csc x=csc x-1/cot x
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\[\frac{ \cot x }{ 1+cosec x }= cosec x- \frac{ 1 }{ \cos x }??\]
no,the right side is =(csc x-1)/cot x
can someone help me,plz?
\[\frac{ cotx }{ 1+cosecx }*\frac{ (1-cosec x) }{ (1-cosec x) }\] \[=\frac{ cotx *(1-cosec x) }{ (1-cosec ^{2}x) }\]
also, we know that \[1+ \cot ^{2}x=cosec ^{2}x\] \[1- cosec ^{2}x= - \cot ^{2}x\] putting this value in above equation. \[\frac{ \cot x*(1-cosecx) }{ - \cot ^{2}x }= \frac{ -(1-cosecx )}{ \cot x }=\frac{ cosecx -1 }{ \cot x }\]
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thnku sooooooo much @neer2890 and @RaphaelFilgueiras :)
you're welcome........:)
you are welcome
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