Question

how many real-number solutions does this equation have?
-8x^2-8x-2=0
a. one solution
b. two solutions
c. no solutions
d. infinetly many solutions

Answer 1

To answer the question `how many real-number solutions does the equation have` I would solve it.

\(\normalsize\color{blue}{ -8x^2-8x-2=0 }\) factor the left side out of `-2`
\(\normalsize\color{blue}{ -2(4x^2+4x+1)=0 }\) divide both sides by `-2`
\(\normalsize\color{blue}{ 4x^2+4x+1=0 }\)
\(\normalsize\color{blue}{ (2x+1)^2=0 }\) square root both sides,
\(\normalsize\color{blue}{ 2x+1=0 }\)

Answer 2

Let me know if you need more help solving the equation, and determining the number of REAL solutions.

Answer 3

no thanks! thank you so much that helped alot !!!!!!!!! :)))) @SolomonZelman

Answer 4

Anytime, so how many (real) solutions are there ?