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Geometry 21 Online
OpenStudy (anonymous):

Segment AC is a tangent of Circle O and Circle P Segment AC = 24 Segment OC = 26 Segment OP = 13 Segment BP = ___ Hint: Use the Pythagorean Theorem and then Proportions to find the value

OpenStudy (anonymous):

OpenStudy (anonymous):

13^2+24^2=26^2?

OpenStudy (aum):

OAC is a right triangle. Find OA first. OA^2 + AC^2 = OC^2

OpenStudy (anonymous):

I came up with OA=10

OpenStudy (aum):

correct. Next find PC. PC = OC - OP = ?

OpenStudy (anonymous):

PC=13

OpenStudy (aum):

correct. Triangles BPC and AOC are similar. Therefore, BP / AO = PC / OC BP = PC / OC * AO = ?

OpenStudy (aum):

PC = 13 (see your previous calculation) OA = 10 (see your calculation before that) OC = 26 (given) BP = PC / OC * AO = 13 / 26 * 10 = 10/2 = 5

OpenStudy (anonymous):

Thank you

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