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sin theta 3 /5 find the value of tan θ
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tan theta = sin theta/ cos theta
\[\sin \theta=\frac{ Perpendicular }{ Hypotenuse }\] |dw:1406270997294:dw| using pythagorean theorem in above triangle \[x ^{2}=5^{2}-3^{2}\] \[x ^{2}=16\] x=4 now, \[\tan \theta=\frac{ Perpendicular }{ Base }\] \[\tan \theta=\frac{ 3 }{ 4 }\]
\[\tan \left(\sin ^{-1}\left(\frac{3}{5}\right)\right)=\frac{3}{4} \]
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