Question

Write in exponential form log^9 729=3

Answer 1

\[\left( \log _{9} 279 \right) =3\]
Put a base of 9 for each side
\[9^{(\log _{9} 729)} = 9^{3}\]
The 9 and the base 9 in the log cancel out so you're left with
\[9^{3}=729\]
That is the Exponential form