Question

equation for a line passing through the point (5,1) and (-2,3)

Answer 1

first find the slope from these points
m=y2-y1 / x2 -x1
let
(x1,y1) =(5,1)
(x2,y2)=(-2,3)
then m= 3-1 / -2-5
m=2/ -7
m=- 2/7
now u have slope and points so take any one point from the given data and put both slope and the point into this formula( point slope formula)
(x1,y1)=(5,1)
(y-y1)=m(x-x1)
y-1= - 2 /7 ( x- 5)
7y -7 =-2x+10
7y +2x -7 -10=0
2x+7y -17=0
is the equation of the line
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