2 is a zero of x^3-8x^2+25x-26
Find the remaining zeros.

I used synthetic division to find x^2-6x+13, but I am unsure what to do from there

Question

2 is a zero of x^3-8x^2+25x-26
Find the remaining zeros. 

I used synthetic division to find x^2-6x+13, but I am unsure what to do from there

ikram002p · Answer

well since 2 is zero then x-2 is a factor of it , right ?
then use long division

anonymous · Answer

That is what I did, but would the zeros be 6, -13?

ikram002p · Answer

wait lemme check

ikram002p · Answer

well 
x^3-8x^2+25x-26 = (x+2) ( x^2-6x+13 )
that sounds like complex solution :O

ikram002p · Answer

use the general formula for quadratic equation and set i instead of sqrt -1

ikram002p · Answer

could u do that and solve ( x^2-6x+13 )?

ikram002p · Answer

a=1
b=-6
c=13

anonymous · Answer

so my answers are, (other than 2), 1, -6, 13?

ikram002p · Answer

mmm the answer showld be complex roots

ikram002p · Answer

:O

ikram002p · Answer