Question

2 is a zero of x^3-8x^2+25x-26
Find the remaining zeros.

I used synthetic division to find x^2-6x+13, but I am unsure what to do from there

Answer 1

well since 2 is zero then x-2 is a factor of it , right ?
then use long division

Answer 2

That is what I did, but would the zeros be 6, -13?

Answer 3

wait lemme check

Answer 4

well
x^3-8x^2+25x-26 = (x+2) ( x^2-6x+13 )
that sounds like complex solution :O

Answer 5

use the general formula for quadratic equation and set i instead of sqrt -1

Answer 6

could u do that and solve ( x^2-6x+13 )?

Answer 7

a=1
b=-6
c=13

Answer 8

so my answers are, (other than 2), 1, -6, 13?

Answer 9

mmm the answer showld be complex roots

Answer 10

:O

Answer 11

http://www.wolframalpha.com/input/?i=x^2-6x%2B13