Question

Find the standard form of the equation of the parabola with a focus at (3, 0) and a directrix at x = -3. @aum

Answer 1

@cwrw238

Answer 2

@ganeshie8 @mathmate @mathstudent55

Answer 3

This is a horizontal parabola that opens to the right.
Any point on the parabola is equidistant from the focus and the directrix:
(x-3)^2 + (y-0)^2 = (x - (-3))^2
(x-3)^2 + y^2 = (x+3)^2
y^2 = (x+3)^2 - (x-3)^2
y^2 = (x+3+x-3)(x+3-x+3)
y^2 = 2x * 6 = 12x
x = 1/12 * y^2

Answer 4

thank you

Answer 5

yw.