Question

how to verify rolle's theorem on |9-x^2| on [-3,3] ?

Answer 1

well 3^2 = (-3)^2

so
f(3)=f(-3) = 0

first derivative
f'(x) = -2x = 0
---> x = 0

0 is in interval [-3,3]

Answer 2

what does the |9-x^2| signify? how is it different from just 9-x^2 @dumbcow

Answer 3

oh shoot sorry i didn't notice the abs value
well it signifies that function is always positive