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how to verify rolle's theorem on |9-x^2| on [-3,3] ?
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well 3^2 = (-3)^2 so f(3)=f(-3) = 0 first derivative f'(x) = -2x = 0 ---> x = 0 0 is in interval [-3,3]
what does the |9-x^2| signify? how is it different from just 9-x^2 @dumbcow
oh shoot sorry i didn't notice the abs value well it signifies that function is always positive |dw:1406607996419:dw|
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