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prove that sum of 3 consecutive natural numbers is divisible by 9
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3 consecutive natural numbers. \(\normalsize\color{blue}{ 1+2+3 }\) for example, I doubt that !
Nope sir!! I can prove the opposite though... just did !
`sum of 3 consecutive number` = `middle number in the sum` × `3` So if you middle number in the set of 3 consecutive natural numbers is divisible by 3, then the sum is also divisible by 3.
then the sum is divisible by 9 I meant to say
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