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Lee missed the lesson on normal distribution and needs to do his homework. Explain to Lee how to use the mean and standard deviation of a normal distribution to determine the top 6% of the population.
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Find the z-score that corresponds to 0.94
.9395
ok, what z is that ?
1.5, I think.
@phi
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now you can answer Explain to Lee how to use the mean and standard deviation of a normal distribution to determine the top 6% of the population. 1) Find the z-score that corresponds to 0.94 (= 1 - 0.06) 2) multiply the z * std dev and add to the mean to find the "threshold" only 6% of the population will have a value above this threshold number
I'm sorry, but what is the average in this equation? Or is it working in theoretical terms?
@phi
the mean
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