Question

How would one find the solution for 4cosx-2secx=0?

I have a feeling I'm over thinking the problem.

Answer 1

furthest im getting is 4cosx -1/2cosx = 0

Answer 2

\(\LARGE\color{blue}{ 4\cos x-2\sec x=0 }\)

\(\LARGE\color{blue}{ 2(2\cos x-\sec x)=0 }\)

\(\LARGE\color{blue}{ 2\cos x-\sec x=0 }\)
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\(\LARGE\color{blue}{ 2\cos x-\frac{1}{\cos x}=0 }\) everything times `cos x`

\(\LARGE\color{blue}{ 2\cos^2x-1=0 }\)

\(\LARGE\color{blue}{ 2\cos^2x=1 }\)

\(\LARGE\color{blue}{ \cos^2x=1/2 }\)

\(\LARGE\color{blue}{ \cos x=±\sqrt{1/2} }\)

Answer 3

That would be π /4

Answer 4

alright i have a question now

Answer 5

what happened to the factored 2 does it just disappear?