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How would one find the solution for 4cosx-2secx=0? I have a feeling I'm over thinking the problem.
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furthest im getting is 4cosx -1/2cosx = 0
\(\LARGE\color{blue}{ 4\cos x-2\sec x=0 }\) \(\LARGE\color{blue}{ 2(2\cos x-\sec x)=0 }\) \(\LARGE\color{blue}{ 2\cos x-\sec x=0 }\) ──────────────────────── \(\LARGE\color{blue}{ 2\cos x-\frac{1}{\cos x}=0 }\) everything times `cos x` \(\LARGE\color{blue}{ 2\cos^2x-1=0 }\) \(\LARGE\color{blue}{ 2\cos^2x=1 }\) \(\LARGE\color{blue}{ \cos^2x=1/2 }\) \(\LARGE\color{blue}{ \cos x=±\sqrt{1/2} }\)
That would be π /4
alright i have a question now
what happened to the factored 2 does it just disappear?
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